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Radius And Temperature Calculator

Effective Temperature Formula:

\[ T_{\text{eff}} = \left( \frac{L}{4 \pi \sigma R^2} \right)^{1/4} \]

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1. What is the Effective Temperature Formula?

The effective temperature formula calculates the temperature of a black body that would emit the same total amount of electromagnetic radiation as the object being measured. It's derived from the Stefan-Boltzmann law and is widely used in astrophysics and thermodynamics.

2. How Does the Calculator Work?

The calculator uses the effective temperature formula:

\[ T_{\text{eff}} = \left( \frac{L}{4 \pi \sigma R^2} \right)^{1/4} \]

Where:

Explanation: The formula relates the temperature of an object to its luminosity and radius through the Stefan-Boltzmann law, which states that the total energy radiated per unit surface area is proportional to the fourth power of the temperature.

3. Importance of Effective Temperature Calculation

Details: Calculating effective temperature is crucial in astrophysics for determining stellar temperatures, in climate science for planetary temperature estimates, and in various engineering applications involving thermal radiation.

4. Using the Calculator

Tips: Enter luminosity in watts (W), radius in meters (m). Both values must be positive numbers. The Stefan-Boltzmann constant is fixed at 5.67 × 10⁻⁸ W/m²K⁴.

5. Frequently Asked Questions (FAQ)

Q1: What is the Stefan-Boltzmann constant?
A: The Stefan-Boltzmann constant (σ) is a physical constant that relates the total energy radiated per unit surface area of a black body to the fourth power of its temperature. Its value is approximately 5.67 × 10⁻⁸ W/m²K⁴.

Q2: Can this formula be used for non-black bodies?
A: The formula gives the effective temperature, which is the temperature a black body would need to have to radiate the same total power. For real objects, this provides an approximation that may need correction factors for emissivity.

Q3: What are typical values for stellar temperatures?
A: Stellar temperatures range from about 2,000-3,000 K for red dwarfs to over 30,000 K for blue supergiants. Our Sun has an effective temperature of about 5,778 K.

Q4: How does radius affect effective temperature?
A: For a given luminosity, a larger radius results in a lower effective temperature because the same amount of energy is spread over a larger surface area.

Q5: What units should I use for the inputs?
A: Luminosity should be in watts (W), radius in meters (m), and the resulting temperature will be in kelvin (K). Make sure all units are consistent for accurate results.

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